The basic hyperboloid of one sheet is given by the equation $$\frac{x^2}{A^2}+\frac{y^2}{B^2} - \frac{z^2}{C^2} = 1$$ The hyperboloid of one sheet is possibly the most complicated of all the quadric surfaces. For one thing, its equation is very similar to that of a hyperboloid of two sheets, which is confusing. (See the section on the two-sheeted hyperboloid for some tips on telling them apart.) For another, its cross sections are quite complex.
Having said all that, this is a shape familiar to any fan of the Simpsons, or even anybody who has only seen the beginning of the show. A hyperboloid of one sheet looks an awful lot like a cooling tower at the Springfield Nuclear Power Plant.
Below you can see the cross sections of a simple one-sheeted hyperboloid with \(A=B=C=1\). The horizontal cross sections are ellipses — circles, even, in this case — while the vertical cross sections are hyperbolas. The reason I said they are so complex is that these hyperbolas can open up and down or sideways, depending on what values you choose for \(x\) and \(y\). Check the example and see for yourself. Yikes! If you do these cross sections by hand, you have to check an awful lot of special cases.
The constants \(A\), \(B\), and \(C\) once again affect how much the hyperboloid stretches in the \(x\)-, \(y\)-, and \(z\)-directions. You can see this for yourself in the second picture, which shows the portion of the hyperboloid between the planes \(z=-3\) and \(z=3\).
One caveat: the picture only shows a small portion of the hyperboloid, but it continues on forever in the vertical direction. If you know something about partial derivatives, you could investigate how quickly \(z\) changes with respect to \(x\) and \(y\) for different values of \(C\). You could also explore why adjusting \(C\) seems to have a more dramatic effect than changing \(A\) and \(B\).
Here are a few more points for you to consider.